Question

if x=2p-3q, z=q-3p, y=p+2q find the value of x²+y²+z²+2yz+2zx+2xy.please hurry up...... urgent please....... ​

Answer 1

$\boxed{\huge{\bf{\pink{Answer:}}}}$

0

Step-by-step explanation:

$Given \ x=2p-3q ,\ z=q-3p \ and \ y=p+2q\\\\First \ let \ us \ add \ which \ is \ given \ in \ question\\\\(x+y+z)=2p-3q+q-3p+p+2q\\\\(x+y+z)=3p-3p+3q-3q\\\\(x+y+z)=0\\\\Now \ squaring \ on \ both \ side\\\\(x+y+z)^2=(0)^2\\\\Using \ identity \ (a+b+c)^2=(a^2+b^2+c^2+2ab+2bc+2ca)\\\\(x^2+y^2+z^2+2yz+2zx+2xy)=0\\\\So \ we \ get \ our \ answer \ 0$

Hope it is clear to you.

Answer 2

Step-by-step explanation:

(x+y+z)^2= x^2+y^2+z^2+2xy+2yz+2zx

so (x+y+z)^2=(2p-3q+q-3p+p+2q )^2

so arrange it

(2p-3p+p-3q+q+2q)^2

=(0)^2

answer is 0