if x=2upon 3+root7 then find value of (x-3) squre
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x=2/3+✓7=(2+3✓7)/3
therefore x-3=(2+3✓7-3)/3
x-3= (3✓7-1)/3=✓7-1/3
therefore x-3=(2+3✓7-3)/3
x-3= (3✓7-1)/3=✓7-1/3
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