Question

if x,2x,3x,4x,140and160 are the angle hexagon find the sizes unknown angle​

Answer 1

Step-by-step explanation:

sum of all angles of hexagon =720degree

x+2x+3x+4x+140+160=720

10x+300=720

10x=720-300

10x=420

x=420/10

x=42

2x=42*2=84

3x=42*3=126

4x=42*4=168

Answer 2

Answer:

there fore, sizes of unknown angles are:-

x=42 ,2x= (42x2)= 84^o , 3x= (42x3)= 126x=48 ,2x= (48x2)=96^o, 3x=(48x3)=144and 4x =( 4x42)= 168^o

Step-by-step explanation:

As we know that sum of angle of a hexagon=720^o

x+2x +3x+ 4x + 140 +160=720^o

(10x+300)=720^o

10x=720-300=420

x=480/10= 42

there fore, sizes of unknown angles are:-

x=42 ,2x= (42x2)= 84^o , 3x= (42x3)= 126x=48 ,2x= (48x2)=96^o, 3x=(48x3)=144 and 4x =( 4x42)= 168^o

...............................................................................................................................................................................................................................................................................................................Hope its help you brooo.