Math, asked by Nerdymind, 1 year ago

If x-2y=11 and xy=8, find x^3-8^3

Answers

Answered by chandradar11gmailcom
1
xy=8
y=8/x
x-2y=11
x-2×8/x=11
x^2-16=11x
x^2+11x=16
x(x+11)=16
x=16;x=16-11=5

x^3-8^3=5^3-8^3=387
x^3-8^3=16^3-8^3=3584
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