If x - 2y, 2x - y, 3x, ........., 11x + 8y are terms of an Arithmetic Progression,
then their sum is .....
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Soln: Let the numbers are x and y. One of them must be greater than or equal to the other. Let us assume that x is greater than or equal to y.
The sum of the two numbers is 8. Thus, we have x+y = 8
The sum of the two numbers is four times their difference. Thus, we have
x+y = 4(x— y)
=>x+y= 4x-4y
=>4x — 4y—x—y = 0
=> 3x-5y = 0
So, we have two equations
x+y=8
3x-5y = 0
Here x and y are unknowns.
We have to solve the above equations for x and y.
Multiplying the first equation by 5 and then adding with the second equation, we have
5(x + y)+(3x — 5y) = 5×8+0
=>5x+5y+3x-5y =40
=>8x = 40
=> x = 5
x = Substituting the value of x in the first equation, we have
5+y=8
=>y=8-5
=>y=3
Hence, the numbers are 5 and 3.
adarsh125634:
options for this question. 1> 33(2x+y) 2> 22(2x+y) 3>28(x+y) 4> 33x+11y
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