if x + 2y + 3z = 14,
2x + 3y + z = 11 and
3x + y + 2z = 11,
find (x + y + z)
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Answer:
- Step-by-step explanation: X² + 2y + 3z = 14
- `x² + 2y + 3z - ( x² + 3z ) = 14 - (X² + 3z )
- 2y / 2 = 14 - x² - 3z
- y = 14 - x² - 3z / 2
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