Math, asked by shubashish8387, 1 year ago

if x + 2y + 3z = 14,
2x + 3y + z = 11 and
3x + y + 2z = 11,
find (x + y + z)​

Answers

Answered by shevysheldon1270
3

Answer:

  1. Step-by-step explanation: X² + 2y + 3z = 14
  2. `x² + 2y + 3z - ( x² + 3z ) = 14 - (X² + 3z )
  3. 2y / 2 = 14 - x²  - 3z
  4. y = 14 - x² - 3z / 2

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