Question

if x=2y+6 find the value of x^3-8y^2-36xy-216

Answer 1

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Step-by-step explanation:

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Answer 2

Answer:

Answer

x

3

−8y

3

−36xy−216

=x

3

+(−2y)

3

+(−6)

3

−3(x)(−2y)(−6)

=(x−2y−6)(x

2

+4y

2

+36+2xy−12y+6x)

=0×(x

2

+4y

2

+36+2xy−12y+6x)

=0

Step-by-step explanation:

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