If x=2y+6, then find the value of x^3-8y^3-36xy-216
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Solution :-
Given : x = 2y + 6 ; We have to find the value of x³ - 8y³ - 36xy - 216
Substituting the value of x = 2y + 6 in the above, we get.
⇒ (2y + 6)³ - 8y³ - 36(2y + 6)y - 216
⇒ (2y + 6)*(2y + 6)*(2y + 6) - 8y³ - 36*(2y + 6)*y - 216
⇒ 8y³ + 72y² + 216y + 216 - 8y³ - 72y² - 216y - 216
⇒ 8y³ - 8y³ = 0
⇒ 72y² - 72y² = 0
⇒ 216y - 216y = 0
⇒ 216 - 216 = 0
Hence, the answer is 0.
Given : x = 2y + 6 ; We have to find the value of x³ - 8y³ - 36xy - 216
Substituting the value of x = 2y + 6 in the above, we get.
⇒ (2y + 6)³ - 8y³ - 36(2y + 6)y - 216
⇒ (2y + 6)*(2y + 6)*(2y + 6) - 8y³ - 36*(2y + 6)*y - 216
⇒ 8y³ + 72y² + 216y + 216 - 8y³ - 72y² - 216y - 216
⇒ 8y³ - 8y³ = 0
⇒ 72y² - 72y² = 0
⇒ 216y - 216y = 0
⇒ 216 - 216 = 0
Hence, the answer is 0.
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