if x+2y=8 and xy=2 find the value of x2+4y2
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Step-by-step explanation:
x+2y=8
squaring on both sides
(x+2y)^2=8^2
x^2+4y^2+4xy=64
x^2+4y^2+4(2)=64
x^2+4y^2=64-8
x^2+4y^2=56
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