if x-2y+k=0 is a median of the triangle whose vertices are at points A(-1,3),B(0,4),C(-5,2),FIND THE VALUE OF K
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Median is a line which passes through the vertex of a triangle divides the opposite side in the ratio 1:1 .
If we take the following cases
CASE1:
If AD is the median then it must pass through the midpoint of B and C
so applying midpoint formula
(+/2,+/2)
∴ D≡(-5/2,3) So it satisfies the median AD
∴ -5/2-2*3+K=0 ⇒k=17/2
CASE 2:
If BE is the median then it must pass through the midpoint of A and C
∴E≡(-3,5/2) So it satisfies the equation of median
-3-2*5/2+k=0 ⇒k=8
CASE 3
If CF is the median where F is the midpoint of A and B
∴It satisfies the equation median
-1/2-2*7/2+k=0
∴ k=15/2
If we take the following cases
CASE1:
If AD is the median then it must pass through the midpoint of B and C
so applying midpoint formula
(+/2,+/2)
∴ D≡(-5/2,3) So it satisfies the median AD
∴ -5/2-2*3+K=0 ⇒k=17/2
CASE 2:
If BE is the median then it must pass through the midpoint of A and C
∴E≡(-3,5/2) So it satisfies the equation of median
-3-2*5/2+k=0 ⇒k=8
CASE 3
If CF is the median where F is the midpoint of A and B
∴It satisfies the equation median
-1/2-2*7/2+k=0
∴ k=15/2
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