Question

If x=√3+1/√3-1 and y=√3-1/√3+1,then the value of X2+y2 is​

Answer 1

Given:

x=$\frac{√3+1}{√3-1}$

y=$\frac{√3-1}{√3+1}$

Find:

${x²+y²}$

Answer:

=$\frac{5}{2}$

=${2.5}$ or ${2{\frac{1}{2}}}$

Explanation:

=$\frac{√3+1}{√3-1}$² + $\frac{√3-1}{√3+1}$²

=$\frac{3+1}{3-1}$ + $\frac{3-1}{3+1}$

=$\frac{4}{2}$ + $\frac{2}{4}$

=$\frac{2}{1}$ + $\frac{1}{2}$ (divided by 2)

=$\frac{2×2}{1×2}$ + $\frac{1}{2}$ (LCM= 2)

=$\frac{4}{2}$ + $\frac{1}{2}$

=$\frac{5}{2}$

=${2.5}$ or ${2{\frac{1}{2}}}$