if X=√3+1/√3-1 , XY=1 than X2+Y2/X2-Y2 =?
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Answered by
0
Answer:
Given, x=2+
3
and xy=1
⇒y=
x
1
=
2+
3
1
=2−
3
x
=
2+
3
=
2
1
(
4+2
3
)−
2
3
+1
2
+
x
=
2
+
2
2
=
2
2+
3
+1
=
2
3+
3
2
−
y
=
2
−
2
3
−1
=
2
2−
3
+1
=
2
3−
3
∴
2
+
x
x
+
2
−
y
y
=
2
3+
3
2+
3
+
2
3−
3
2−
3
=
3+
3
2
2
+
6
+
3−
3
2
2
−
6
=
(3+
3
)(3−
3
)
6
2
−2
6
+3
6
−3
2
+2
6
−3
6
−3
2
=
9−3
6
2
=
2
Step-by-step explanation:
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