Question

if x = (√3-1/√3+1) , y= (3+2√2/3-2√2)
then find the value of x + Y

Answer 1

x = √3-1/√3+1

→ √3-1/√3+1 × √3-1/√3-1

→ (√3-1)(√3-1)/(√3+1)(√3-1)

→ (√3-1)²/(√3²-1²)

→ (√3²+1²-2(√3)(1))/(3-1)

→ (3+1-2√3)/2

→ (4-2√3)/2

→ 2-√3

y = (3+2√2)/(3-2√2)

→ (3+2√2)/(3-2√2)×(3+2√2)/(3+2√2)

→ (3+2√2)(3+2√2)/(3-2√2)(3+2√2)

→ (3+2√2)²/(3²-(2√2)²)

→ [3²+(2√2)²+2(3)(2√2)]/(9-4(2))

→ (9+8+12√2)/(9-8)

→ 17+12√2

x+y = 2-√3+17+12√2

= 19-√3+12√2

Hope it helps

Answer 2

Hope it helps
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