if x= √3+1 find the value of (x+2/x)²
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x=2+√3
1/x=1/2+√3
=1*(2-√3)/(2+√3)/(2-√3)
=(2-√3)/(2^2-√3^2)
=(2-√3)/4-3
=(2-√3)
Therefore,
x^2=(2+√3)
=(2)^2+(√3)^2+2*2*(√3)
=4+3+4√3
=7+4√3
1/x^2=(2-√3)^2
=(2)^2+(√3)^2-2*2*√3
=4+3-4√3
=7-4√3
x^2+1/x^2
=(7+4√3)+(7-4√3)
=7+4√3+7-4√3
=7+7+4√3-4√3
=14
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