If x= 3+2√2 and y = 1/x , then the value of x² + y² will be
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Answer:
The formulas used are...
- (a+b)(a-b)=a^2-b^2
- (x+y)^2+(x-y)^2=2(x^2+y^2)
Step-by-step explanation:
x=3+2√2. y= 1. (3-2√2)
(3+2√2)(3-2√2)
y=3-2√2
x^2+y^2=(3+2√2)^2+(3-2√2)^2
=2(3^2+(2√2)^2)
=2(9+8)=2×17=34
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