If x = 3 + 2√2: find the value of
![\sqrt{x } + \frac{1}{ \sqrt{x} } \sqrt{x } + \frac{1}{ \sqrt{x} }](https://tex.z-dn.net/?f=+%5Csqrt%7Bx+%7D+%2B+++%5Cfrac%7B1%7D%7B+%5Csqrt%7Bx%7D+%7D+)
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9th grade
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putting the value of x in it
√3+2√2+1/√3+2√2
now root and root cancles
so
2√5+1/2√5
now making the denominator same
we get
20/2√5+1/2√5=. 21/2√5
make it brainest it took a long time in typing all this
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