if x=3+2√2, find the value of (x-1/x)^3
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Answer:
(x-1/x)^3 = 128√2
Step-by-step explanation:
x = 3+2√2
1/x = 1 / (3+2√2)
1/x = (3-2√2)/( [3+2√2]*[3-2√2] ) (Since Rationalization)
1/x = (3-2√2)/9-8
1/x = (3-2√2)
So (x-1/x)^3
=> ( 3+2√2 - ( 3 - 2√2)^3
=>(3+2√2-3+2√2)^3
=>(4√2)^3
=>64*2√2
=>128√2
Hope helps you
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