Math, asked by rminisingh1980, 6 months ago


If x = 3 - 2√2, find thevalue of √x+1+√x​

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Answered by Anonymous
14

 \star \:  \:  \:  \: { \underline \blue{Given }} :

 \hookrightarrow \:  \tt \: x = 3 - 2 \sqrt{2}

 \star \:  \:  \:  \: { \underline \blue{To  \:  \: Find }} :

 \hookrightarrow \tt \:  \sqrt{x}  +  \frac{1}{ \sqrt{x} }  =  {?} \\

 \star \:  \:  \:  \: { \underline \blue{Solution}} :

 \dashrightarrow \:  \tt\: x = 3 - 2 \sqrt{2}

 \dashrightarrow   \tt \: \sqrt  x =  \sqrt{3 - 2 \sqrt{2} } \\

 \tt \red \: {Now,}

 \looparrowright \:  \:  \tt\:  \sqrt{x}  +  \frac{1}{ \sqrt{x} }   \\

 \tt \dashrightarrow \:  \frac{x + 1}{ \sqrt{x} }  \\

 \tt \orange{ Putting  \:  \: value  \:  \: of  \:  \: x \:  \:  and \:  \:  √x}

 \tt\dashrightarrow \:  \frac{3 -  2\sqrt{2}  + 1}{ \sqrt{(3 -  2\sqrt{2}) } }  \\

 \dashrightarrow \: \tt  \frac{2(2 -  \sqrt{2} )( 3 + 2 \sqrt{2}) }{ \sqrt{(3 - 2 \sqrt{2} )(3 + 2 \sqrt{2} )} }  \\

 \dashrightarrow  \tt\: 12 + 8 \sqrt{2}  - 3 \sqrt{2}  - 2

 \dashrightarrow  \underline{ \boxed{ \mathfrak{ 10 - 5 \sqrt{2} }}}

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 \star  \:  \:  \blue{\mathbb{HOPE  \:  \: THIS \:  \:  IS  \:  \: HELPFUL}}  \:  \: \star

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