If x= 3-2√2. Find value of x^3-1/x^3
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x³-1/x^3
-140√2
Given X= 3-2√2 _____(1)
(1) 1/x = 1/3-2√2
Rationalising the denominator we get,
3+2√2/(3-2√2)(3+2√2)
3+2√2/3² - (2√2)^2
3+2√2/9-8
3+2√2 ________(2)
(2) x - 1/x
3 - 2√2 - (3+2√2)
3 - 2√2 - 3 - 2√2
-4√2__________(3)
Algebraic identity
a^3 - b^3 = (a + b)^3 + 3ab(a - b)
x^3 - 1/x^3
(x - 1/x)^3 + 3 × x × 1/x( x - 1/x)
(-4√2)^3 + 3(-4√2)
-128√2 - 12√2
-140√2
Thanks ❤️
hope it helps you.❤️
silentlover45.❤️
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