If x = 3 + 2√2 find √x + 1/√x
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Given that,
x = 3+2√2
=> √x = √3+2√2
= √1+2+2.1.√2
= √(1+√2)²
= 1+√2
1/√x = 1/1+√2
On rationalisation, it will be
1/√x = 1 - √2
Therefore,
√x + 1/√x = (1 + √2) + (1 - √2)
= 2
hope it helps.....
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