Math, asked by Akbaba, 1 year ago

If x=3-2√2,findx3-1/x3

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Answered by aman190k
1
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given \: . \\  \\ x = 3 - 2 \sqrt{2}  \\  \\  \frac{1}{x}  =  \frac{1}{3 - 2 \sqrt{2} }  \\  \\  =  \frac{1}{3 - 2 \sqrt{2} }  \times  \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} }  \\  \\ =   \frac{3 + 2 \sqrt{2} }{ {(3)}^{2}  -  {(2 \sqrt{2}) }^{2} }  \\  \\  =  \frac{3 + 2 \sqrt{2} }{9 - 4 \times 2}  \\  \\  =  \frac{3 + 2 \sqrt{2} }{9 - 8} \\  \\   = 3  + 2 \sqrt{2}  \\  \\ now \: .by \: using \: identity :  \:  \\  \\  = {a}^{3}  -  {b}^{3}  \\  \\  = (a - b)( {a}^{2}  + ab +  {b}^{2})  \\  \\ then :   \\  \\    = {x}^{3}  -  { (\frac{1}{x} )}^{3}  \\  \\ =  (x -  \frac{1}{x})( {x}^{2}    + x \times  \frac{1}{x}  +  {( \frac{1}{x}) }^{2} ) \\  \\  putting \: the \: value \: of \: x \: and \:  \frac{1}{x}   \: w e \: get:  \\  \\ =  (3 - 2 \sqrt{2}  - 3 - 2 \sqrt{2} )( {(3 - 2 \sqrt{2}) }^{2}  + 1 +  {(3 + 2 \sqrt{2}) }^{2} ) \\  \\  =  (- 4 \sqrt{2} )(9 + 8 - 12 \sqrt{2} + 1 + 9 + 8 + 12 \sqrt{2}) \\  \\  = ( - 4 \sqrt{2} )(  35) \\  \\  =  - 140 \sqrt{2}
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