Question

If x = 3 + 2√2 the find the value of ( −1/x)^3+6(x^2+1/x^2)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer

x=3+2√2

1/x=1/3+2√2

=1/3+2√2×3-2√2/3-2√2

=(3-2√2)/(3)^2-(2√2)^2

=(3-2√2)/9-8

=(3-2√2)/1

=3-2√2

(1+1/x)=3+2√2+3-2√2

=9

(1+/x)^2=(9)^2

=81