Question

if x=3-2√2 then find the value of (√x) +(1/√x)​

Answer 1

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$x = 3 - \sqrt[2]{2}$

$\frac{1}{x} = \frac{1}{3 - \sqrt[2]{2} } \frac{(3 + \sqrt[2]{2)} }{(3 + \sqrt[2]{2}) }$

$\frac{1}{x} = \frac{3 + \sqrt[2]{2} }{ {3}^{2} - ( \sqrt[2]{2}) }$

$= 3 + \sqrt[2]{2}$

$x + \frac{1}{x} = (3 - \sqrt[2]{2}) + ( {3 - \sqrt[2]{2} } )$

$x \frac{1}{x} = 6$

$x + \frac{1}{x} = 2 + 4$

$x + \frac{1}{x} - 2 = 4$

$( \sqrt{x} - \frac{1}{x} ) = 4$

$\sqrt{x} - \frac{1}{ \sqrt{x} }$

$= \pm \:2$

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Answer 2

Answer:

your answer attached in the photo