Question

if x=√3+√2/√3-√2&y=√3-√2/√3+√2 find x²+y²?

Answer 1

x=√3+(√6-√2)
y=√3-√6+√2
>>>y=√3-(√6-√2)

x+y=2√3
xy=-5+4√3

x²+y²=(x+y)²-2xy

=(2√3)²-(-5+4√3)
=11+5-4√3
=12+4√3
=4√3(√3+1)

Hope this helps