If x = √3+√2
√3−√2
and y = √3−√2
√3+√2
, find the value of x2 + y2 + xy
TheSETJ:
Clear it out that is x = √3+√2 or x = (√3+√2)/(√3−√2)? Same for y?
If x = √3+√2
√3−√2
and y = √3−√2
√3+√2
, find the value of x2 + y2 + xy.
√3−√2
and y = √3−√2
√3+√2
, find the value of x2 + y2 + xy.
this is the right question
The problem is that what is √3−√2 between 1st and 3rd line. Same question for 4th line. They are not make sense to be there.
Answers
Answered by
12
Given,.
x = √3+√2 / √3−√2
x= 5+2√6
observing we get ,
y= 1/x.
y= 5 - 2√6.
Now.,.
x2 + y2 + xy
...solve it by making complete square!!..
see picture!!.
hope it helped you!!
x = √3+√2 / √3−√2
x= 5+2√6
observing we get ,
y= 1/x.
y= 5 - 2√6.
Now.,.
x2 + y2 + xy
...solve it by making complete square!!..
see picture!!.
hope it helped you!!
Attachments:
Answered by
1
Answer:
Given,.
x = √3+√2 / √3−√2
x= 5+2√6
observing we get ,
y= 1/x.
y= 5 - 2√6.
Now.,.
x2 + y2 + xy
...solve it by making complete square!!..
see picture!!.
hope it helped you!!
Step-by-step explanation:
Similar questions