Question

If x=√3+√2/√3-√2 and y=√3-√2/√3+√2, find x^2+y^2​

Answer 1

Answer:

98

Step-by-step explanation:

AS

X=(√3+√2/√3-√2)X(√3+√2/√3+√2)

WE GET X =3+2-2$\sqrt{6}$/1

=5-2$\sqrt{6}$

SIMILARLY

Y=5-2$\sqrt{6}$

NOW SQUARING AND ADDING WE GET

X^2+Y^2=25+24+20$\sqrt{6}$+25+24-20$\sqrt{6}$

              =50+48

              =98

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