Question

if x=3/2 is one of the roots of equation kx^2-13x+6=0 then find the value of k​

Answer 1

Answer: k ×  (3/2)² - 13 × 3/2 + 6 =0

9/4k -39/2 + 6 =0

9/4k -27/2 =0

k=6

Answer 2

Answer:

6

Step-by-step explanation:

kx^2-13x+6=0

substitute x value

k (3/2)^2-13 (3/2)+6=0

9k/4-39/2+6=0

LCM is 4

9K-78+24/4=0

by cross multiplication 0×4=0

9k-78+24=0

9k-54=0

transfer 54

9k=54

transfer 9

k=54/9

k=6