if x = √3+√2 then find x^2+(1/x^2) -3
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Step-by-step explanation:
x=√3+√2
x^2+(1/x^2)-3
(√3+√2)^2+(1/[√3+√2]^2)-3
3+2+2√6+(1/3+2+2√6)-3
5+2√6+1/5+2√6-3
(5+2√6)^2+1-3(5+2√6)/5+2√6
25+24+20√6+1-15-6√6/5+2√6
[35+14√6]/5+2√6
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