Question

IF (x+3)^2+(y-2)^2=0 then x^y=​

Answer 1

Answer:

Given,

(x−a)

2

+(y−a)

2

=0.

Since the sum of two positive numbers is 0 then they must be equal to 0 individually.

So, x−1=0⇒x=a.

Similarly y=a.

Now

y

x

=

a

a

=1.

Answer 2

Given that,

(x-a)

2+(y-a)

2

=0

Since the sum of two positive no is zero then they must be equal to 0 individually

so,. x-1=0=x=a

similarly y-a

Now

y

x

=

a

a

=0