Question

If x=3+313+323x=3+313+323 , then x3−9x2+18x−12=x3−9x2+18x−12=  ​

Answer 1

Answer:

0

Step-by-step explanation:

x=3+3⅓+3⅔

or,(x−3)=3⅓+3⅔

Therefore,

(x−3)3=(3⅓+3⅔)3

or,x3−27−9x2+27x=3+9+3×3(3⅓+3⅔)

or,x3−27−9x2+27x=12+9(x−3)[Puttingthevalue(x−3)=(3⅓+3⅔)]

or,x3−27−9x2+27x=12+9x−27

or,x3−27−9x2+27x−12−9x+27=0

or,x3−9x2+18x−12=0(Answer)

Answer 2

Answer:

0

Step-by-step explanation:

x=3+3⅓+3⅔

or,(x−3)=3⅓+3⅔

Therefore,

(x−3)3=(3⅓+3⅔)3

or,x3−27−9x2+27x=3+9+3×3(3⅓+3⅔)

or,x3−27−9x2+27x=12+9(x−3)[Puttingthevalue(x−3)=(3⅓+3⅔)]

or,x3−27−9x2+27x=12+9x−27

or,x3−27−9x2+27x−12−9x+27=0

or,x3−9x2+18x−12=0(Answer)

Step-by-step explanation: