if x=3+4i and y=3-4i, then find: x^2+y^2
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Complex numbers :
• A complex number is of the form (a + ib), where both a and b are real numbers and i is the square root value of (- 1).
• Any real number can be expressed as a complex number.
• The set of complex number is the superset of all others sets like, Real numbers, Natural numbers.
• Two numbers (a + ib) and (a - ib) are called conjugate complex numbers, and its product is always a real number.
Given data is
x = 3 + 4i and y = 3 - 4i
Solution :
Now, x² + y²
= (3 + 4i)² + (3 - 4i)²
= 9 + 24i + 16i² + 9 - 24i + 16i²
{ identity rule : (a + b)² = a² + 2ab + b² }
= 18 + 32i²
= 18 + 32 (- 1), since i² = - 1
= 18 - 32
= - 14
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