If x^3-5x^2-px+24=(x-4).q (x). what is the value of p
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Answer:
p value =2
Step-by-step explanation:
(x-4)=0
x=0+4
x=4
(4)³-5(-4)²-p(4)+24=0
64-80-4p+24=0
88-80-4p=0
8-4p=0
-4p=0-8
p=-8/-4
minus minus cancel
p=2/1
p=2
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