Question

If x=3+√8 and y=3-√8 find the value of 1/x^2 + 1/y^3​

Answer 1

Answer:

GIVEN ;- X=3+ROOT8 AND Y=3-ROOT8

Step-by-step explanation:

NOW, 1/(3+ROOT8)^2+1/(3+ROOT8)^2

1/(9+8+6ROOT8) + 1/(9+8-6ROOT8)

1/(17+6ROOT8) + 1/(17-6ROOT8)

TAKING LCM, WE GET

17-6ROOT8 + 17+6ROOT8/(17+6ROOT8)(17-6ROOT8)

34/289-102ROOT8+102ROOT8-288

34/1=34