if x^3 + 8y^3 + x^3y^3 = 6x^2y^2 where x, y belongs to real nos except 0 and x not equal to 2y. find: 2/x+1/y.
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Answer:
x
3
−8y
3
−36xy−216
=x
3
+(−2y)
3
+(−6)
3
−3(x)(−2y)(−6)
=(x−2y−6)(x
2
+4y
2
+36+2xy−12y+6x)
=0×(x
2
+4y
2
+36+2xy−12y+6x)
=0
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