if (x-3) a factor of (2x²+x+k) find k please can u help me my dav boards are aheah
Answers
Answered by
1
x-3=0
x=3
putting value of x
2x²+x+k=0
2(3)²+3+k=0
18+3+k=0
21+k=0
k=-21
x=3
putting value of x
2x²+x+k=0
2(3)²+3+k=0
18+3+k=0
21+k=0
k=-21
PeehuChouksey:
pls mark it as brainliest
brainliest
but u didn't explain mych that Priya sharma explain es
sorry
Prerna not Priya
Answered by
0
Hiii...
here is ur answer=>>
x-3 = 0
=> x= 3
so zero of the polynomial is 3
Putting x=3 in the above polynomial we get ,
p(3) =0
=> 2×(3)^2+3+k= 0
=> 18 +3+k=0
=>21+k=0
=> k= -21
Hope it helps u !!!
☺☺☺☺☺☺
here is ur answer=>>
x-3 = 0
=> x= 3
so zero of the polynomial is 3
Putting x=3 in the above polynomial we get ,
p(3) =0
=> 2×(3)^2+3+k= 0
=> 18 +3+k=0
=>21+k=0
=> k= -21
Hope it helps u !!!
☺☺☺☺☺☺
mark brainliest plz!
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