if x-3 and x-1/3 are both factor of a ax^2+ 5x+ b , show that a=b
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Answered by
1
hi friend!!!!
Given, x-3 and x-1/3 are both factor of a ax^2+ 5x+ b which means 3,1/3are the zeros of the polynomial
we know that product of zeros =c/a
3(1/3)=c/a
1=c/a
c=a
hence proved.
I hope this will help u ;)
Given, x-3 and x-1/3 are both factor of a ax^2+ 5x+ b which means 3,1/3are the zeros of the polynomial
we know that product of zeros =c/a
3(1/3)=c/a
1=c/a
c=a
hence proved.
I hope this will help u ;)
Answered by
0
hi friend,
x-3 and x-⅓ are the factors of the polynomial,
x-3 = 0 ; x = 3
x-⅓ = 0 ; x = ⅓
therefore,3 and ⅓ are the zeroes of the given polynomial.
we know the relationship between zeroes and coefficients:-
Product of zeroes = constant/x² coefficient
(3)(⅓) = b/a
1 = b/a
a = b
hence proved.
hope it helps
x-3 and x-⅓ are the factors of the polynomial,
x-3 = 0 ; x = 3
x-⅓ = 0 ; x = ⅓
therefore,3 and ⅓ are the zeroes of the given polynomial.
we know the relationship between zeroes and coefficients:-
Product of zeroes = constant/x² coefficient
(3)(⅓) = b/a
1 = b/a
a = b
hence proved.
hope it helps
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