If ( x^3+ax^2-bx+10 ) has (x-2) as a factor and leaves a remainder 3 when divided by x-3,then find the values of a and b
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Hi buddy
Here is your answer
2(-3)+b+7=0
2(-3)+b+7=0=> -6+b+7=0
2(-3)+b+7=0=> -6+b+7=0=> b+1=0=> b = -1Therefore,
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