If (x-3) is a factor of the polynomial (2x^2+x+k)....then find the value of k
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Answers
Answered by
1
Answer:
x-3=0
x=3
substitute x=3 in the equation given
2(3)^2+3+k=0
2(9)+3+k=0
k= -21
answer is minus 21
Answered by
1
Answer:
x-3)2x²+x+k(2x+7
2x²-6x
7x+k
7x-21
0.
=> k-(-21)=0
=> k=-21
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