If (x-3) is a factor of the polynomial (2x²+x+k), find k
please Answer this I'll mark as brainliest
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Answered by
0
Answer:
-21
Step-by-step explanation:
zero of the polynomial x-3 is 3
So,
p(x)=(2x²+x+k)=0
p(3)=[2(3)²+3+k]=0
p(3)=[2(9)+3+k]=0
p(3)=18+3+k=0
p(3)=21+k=0
p(3)=k=0-21
p(3)=k=-21
Answered by
1
Hey mate!!!
In answer there is x instead of k and nothing....
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