if x-3 is a factor of x ^2 + kx +9 , then find the value of k
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x=3 then put the values of x in the equation and equal to 0
3^2+3k+9=0
3k=-18
k= -6
whenever you find these type of questions , just put the value of x in the equation and you will find your answer immediately
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Given :
(x-3) is a factor of x² + Kx +9
To Find :
The value of K
Theory :
The factor theorem states that if f(x) is a polynomial of degree n ≥1 and 'a' is any real number, then (x-a) is a factor of f(x) if f(a)=0.
Solution :
Let F(x)= x²+Kx+9
It is given that (x-3) is a factor of F(x)
Thus , by factor theorem ;
F(3)= 0
(3)²+K(3)+9= 0
9+3k+9=0
18=-3K
K= -6
Hence , the value of K is -6
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