If (x–3) is a factor of x^3 – 2x^2 – 9x + 18 then find the other two factors.
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firstly ,
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6=x(x-2)+3(x-2)
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6=x(x-2)+3(x-2)(x+3) (x-2)=0
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6=x(x-2)+3(x-2)(x+3) (x-2)=0x+3=0 and x-2=0
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6=x(x-2)+3(x-2)(x+3) (x-2)=0x+3=0 and x-2=0then the 2 zeroes are
firstly ,we need to divide x^3 – 2x^2 – 9x + 18 by x-3then the outcome is x²+x-6and just factorise x²+x-6=x²-2x+3x-6=x(x-2)+3(x-2)(x+3) (x-2)=0x+3=0 and x-2=0then the 2 zeroes are-3 and 2
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