if x+3 is a factor of x^3-7x^2-7kx+9x then k is equal to
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______________________________
First of all I'm useless user.
Here is ur answer
given us,
x + 3 = 0
=> x = - 3
we found x = - 3
putting value of x in x³ - 7x² - 7kx + 9x
= ( - 3 )³ - 7 ( - 3 )² - 7k ( - 3 ) + 9 ( - 3 )
= - 27 - 63 + 21k - 27
= 21k - 105
so
21k - 105 = 0
=> 21k = 105
=> k = 105/21
=> k = 5
we found k = 5
thanks!
______________________________
First of all I'm useless user.
Here is ur answer
given us,
x + 3 = 0
=> x = - 3
we found x = - 3
putting value of x in x³ - 7x² - 7kx + 9x
= ( - 3 )³ - 7 ( - 3 )² - 7k ( - 3 ) + 9 ( - 3 )
= - 27 - 63 + 21k - 27
= 21k - 105
so
21k - 105 = 0
=> 21k = 105
=> k = 105/21
=> k = 5
we found k = 5
thanks!
______________________________
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