Question

if x=3 is a root of equation x^3 +3x^2-px+p=0 then find the value of p ​

Answer 1

Given x = 3

Put x = 3 in the equation

==> ( 3)^3 + 3 (3)^2 - 3p +p =0

27 + 81 - 2p = 0

108 = 2p

p = 108/2

p= 54

i. e the value of p is 54

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