Question

if x=3 is a solution of equation (k+2)x^2-kx+6=0, find the value of k .hence, find the other root of eqn​

Answer 1

Answer:

(k+2)x²-kx+6

(k+2)3²-k(3)+6=0

(k+2)9-3k+6=0

9k+18-3k+6=0

6k+24=0

6k=-24

K=-24/6

k=-4