If x=3 is a solution of the quadratic equation x2+kx-6=0 then, find the value of k
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Answered by
8
If x=3 then,
P(3)=3(2)+k(3)-6=0
P(3)=6+3k-6=0
P(3)=6-6+3k=0
i. e- 3k=0
K=0/3
P(3)=3(2)+k(3)-6=0
P(3)=6+3k-6=0
P(3)=6-6+3k=0
i. e- 3k=0
K=0/3
Answered by
5
p(x)=3×2+k×3-6
6+k-18
-12+k
k=12
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6+k-18
-12+k
k=12
hope it helps u
plz follow me
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