If x=3 is one of the quadratic equation x²-2k-6=0 then find the value of k
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put the value of x in the given eqn. .....
3 sq. - 2 k - 6= 0
9 -2k -6 = 0
-2k = -3
k = 3/2 ... it's ur answer
3 sq. - 2 k - 6= 0
9 -2k -6 = 0
-2k = -3
k = 3/2 ... it's ur answer
AMANPATHAK1:
i think your answer is wrong
Answered by
1
x²-2k-6. (x=3)
(3)²- 2k -6 =0
9-2k-6 =0
3-2k =0
-2k = -3
k = 3/2
(3)²- 2k -6 =0
9-2k-6 =0
3-2k =0
-2k = -3
k = 3/2
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