Question

If x= 3 is one root of a quadratic eqn x^ -2kx -6 = 0 find the value of k

Answer 1

Hello friend your answer is
x=3
x²-2kx-6
3²-2k×3-6
9-6k-6=0
3-6k=0
-6k=-3
k=3/6=1/2

Answer 2

x-2kx -6=0


3-6-6k =0

-3=6k

-3/6 =k

-1/2 =k

___________, _,

If the question is
x²-2kx -6=0

3²-(2*3*k) -6=0

9-6-6k =0

3-6k =0

3 =6k

3/6 =k

1/2 =k


I hope this will help you


-by ABHAY