Question

if x=3 is one root of quad equation x
$x {}^{2} - 2kx - 6 = 0$
then find the value of k​

Answer 1

Step-by-step explanation:

If x = 3 is one of root then it will satisfy the equation.....

${x}^{2} - 2kx - 6 = 0 \\ \\ put \: x = 3 \\ \\ {3}^{2} - 6k - 6 = 0 \\ \\ 9 - 6 - 6k = 0 \\ \\ 6k = 3 \\ \\ \boxed{ \boxed{ k = \frac{1}{2} }}$

Answer 2

Step-by-step explanation:

put x=3,

x^2 - 2kx - 6= 0

3^2 - 2×k×3 -6 = o

9- 6k -6 =0

-6k = 6-9

-6k =-3

k =3/6

k =1/2

i hope this will help you