if x = 3 is one root of quadratic equation is
then find the value of k
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x^2-2kx-6=0
(3^2)-2×k×3-6=0
9-6k-6=0
-6k+3=0
-6k=--3
k= --3/ --6
k= 1 / 2
mark me brainliest answer plss
(3^2)-2×k×3-6=0
9-6k-6=0
-6k+3=0
-6k=--3
k= --3/ --6
k= 1 / 2
mark me brainliest answer plss
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