Water flows through a cylindrical pipe whose inner diameter is 1cm at the rate of 80cm per second in an cylindrical tank , the radius of whose base is 40cm. What is the rise of water level in tank in half an hour??.
Answers
Answer:
Step-by-step explanation:
Given, radius of tank, r1 = 40 cm
Let height of water level in tank in half an hour = 1 cm.
Also, given internal radius of cylindrical pipe, r2 = 1 cm
and speed of water = 80 cm/s i.e., in 1 water flow = 80 cm
In 30 (min) water flow = 80x 60 x 30 = 144000 cm According to the question,
Hence, the level of water in cylindrical tank rises 90 cm in half an hour.
Answer:
Inner radius of cylindrical pipe=1cm
Speed of water = 80cm/s
It means,in one sec water flow for a distance of 80 cm
Therefore,water flow in 30min
30×60×80=144000cm
Now, volume of water in cylindrical tank= volume of water flow in the pipe in half an hour.
πr^2h= π^2h2
r^2h1=r^2h2
40×40×h1=1×1×144000
h1= 144000/1600
= 90 cm
Hence, the level of water in the cylindrical tank rises 90 cm in half an hour.